Answer
$$\rho= 2\sec \phi.$$
Work Step by Step
We apply the equations of this section (page 699).
We have $z=\rho \cos \phi=2$. Thus:
$$\rho=\frac{2}{\cos \phi}=2\sec \phi.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 13 - Vector Geometry - 13.7 Cylindrical and Spherical Coordinates - Exercises - Page 700: 65
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