Answer
$(2,0,\frac{\pi}{3})$.
Work Step by Step
Since $ x=\sqrt3, \, y=0, \, z=1$ and
$$\rho=\sqrt{x^2+y^2+z^2},\quad \theta=\tan^{-1}( y/x), \quad \phi=\cos^{-1}(z/\rho),$$
then we have
$$\rho=\sqrt{\sqrt 3^2+0+1^2}=\sqrt{4}=2, $$
$$\theta=\tan^{-1}( 0)=0, $$
$$\phi=\cos^{-1}(1/2)=\frac{\pi}{3}$$
Hence, the spherical coordinates are $(2,0,\frac{\pi}{3})$.
