Answer
$$ \frac{8}{7}$$
Work Step by Step
Given
$$ \frac{1}{1}+\frac{1}{8}+\frac{1}{8^{2}}+\cdots$$
Since the series is a geometric series with $|r|=|1/8|<1$, then the series converges and has the sum
\begin{align*}
S&= \frac{a_1}{1-r}\\
&=\frac{1}{1-\frac{1}{8}}\\
&= \frac{8}{7}
\end{align*}