Answer
\begin{array}{lclcl}
c_1=-1&\\
c_2=-1&\\
c_3=-1&\\
c_4=-1\\
\end{array}
Work Step by Step
Given $$\ \ \ c_n=(-1)^{2 n+1}, \ \ \ \ \ \ n= 1, 2,3, \dots
$$
So, we get
\begin{array}{|l|l|}\hline
& n& \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ c_n \\ \\ \hline
\text{First Term} & 1 & c_1=(-1)^{2 +1}=(-1)^3=-1 \\ \\ \hline
\text{Second Term} & 2 & c_2=(-1)^{4+1}=(-1)^5=-1\\ \\ \hline
\text{Third Term} & 3 & c_3=(-1)^{6+1}=(-1)^7=-1\\ \\ \hline
\text{Fourth Term} & 4 & c_4=(-1)^{8+1}=(-1)^9=-1\\ \\ \hline
\end{array}
