Answer
$0$
Work Step by Step
Since we have
$$\lim_{n\to \infty}c_n=\lim_{n\to \infty}-2^{-n}=\lim_{n\to \infty}-\frac{1}{2^n}=0$$
then the sequence $c_n$ converges to $0$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 11 - Infinite Series - 11.1 Sequences - Exercises - Page 537: 19
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