Answer
$$\sum_{n=1}^{14}\frac{9}{1+n}$$
Work Step by Step
$\frac{9}{1+1}+\frac{9}{1+2}+\frac{9}{1+3}+..+\frac{9}{1+14}$
$$=\sum_{n=1}^{14}\frac{9}{1+n}$$
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