Answer
238
Work Step by Step
$\displaystyle \sum_{i=1}^{4}[(i-1)^{2}+(i+1)^{3}]=$S
There are four terms in the sum :
$i=1:\qquad (0+8)=8$
$i=2:\qquad (1+27)=28$
$i=3:\qquad (4+64)=68$
$i=4:\qquad (9+125)=134$
S$=8+28+68+134=238$
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