Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.2 Exercises - Page 263: 35

Answer

s=0.646 S=0.746

Work Step by Step

Let S be the upper sum and s be the lower sum. Therefore, $S=\frac{1}{5}\Sigma_{x=5}^{9} \frac{1}{x/5} =\frac{1}{5}(\frac{1}{5/5} +\frac{1}{6/5}+ \frac{1}{7/5}+\frac{1}{8/5}+\frac{1}{9/5})$ or $S= \frac{1}{5} +\frac{1}{6}+ \frac{1}{7}+\frac{1}{8}+\frac{1}{9}=0.746$ and $s=\frac{1}{5}\Sigma_{x=6}^{10} \frac{1}{x/5}=\frac{1}{5}(\frac{1}{6/5}+ \frac{1}{7/5}+\frac{1}{8/5}+\frac{1}{9/5}+\frac{1}{10/5})$ or $s= \frac{1}{6}+ \frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10} =0.646$
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