Answer
$2\sin{x}-2\sin{x}+3=3.$
Work Step by Step
$y'=\dfrac{d}{dx}(2\sin{x}+3)=2\cos{x}.$
$y''=\dfrac{d}{dx}(2\cos{x})=-2\sin{x}.$
$-2\sin{x}+2\sin{x}+3=3.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 128: 127
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