Answer
$x^3(\dfrac{2}{x^3})+2x^2(-\dfrac{1}{x^2})=2-2=0.$
Work Step by Step
Using the Power Rule:
$f'(x)=-\dfrac{1}{x^2}$
Using the Power Rule:
$f''(x)=\dfrac{d}{dx}f'(x)=\dfrac{2}{x^3}.$
$x^3(\dfrac{2}{x^3})+2x^2(-\dfrac{1}{x^2})=2-2=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.3 Exercises - Page 128: 125
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