Answer
$-5r^2+4r+3$
Work Step by Step
We divide each term of the polynomial by the monomial as follows
$$
(20r^2 - 16r - 12) \div (-4)=\frac{20r^2 - 16r - 12}{-4}
\\ =\frac{20r^2 }{-4}+\frac{ -16r }{-4}+\frac{ - 12}{-4}\\
=-5r^2+4r+3
.
$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 34
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