Answer
$-\frac{5x^3}{8y^2}$
Work Step by Step
We divide by the monomial as follows
$$
\frac{45x^6}{-72x^3y^2}=\frac{5\cdot 9x^6 }{-8\cdot 9x^3y^2}=-\frac{5x^3}{8y^2}
.$$
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