Answer
$-\frac{23x^2}{7y^2}$
Work Step by Step
We divide by the monomial as follows
$$
\frac{92x^3y}{-28xy^3}=\frac{4\cdot 23x^3y }{-4\cdot 7xy^3}=-\frac{23x^2}{7y^2}
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 25
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