Answer
$\frac{ 8 }{ 7a^3b^2}$
Work Step by Step
We divide by the monomial as follows
$$
\frac{-16a^5b^2}{-14a^8b^4}=\frac{-2\cdot 8a^5b^2 }{-2\cdot 7a^8b^4}=\frac{ 8 }{ 7a^3b^2}
.$$
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