Answer
$-\frac{3}{y}.$
Work Step by Step
We divide by the monomial as follows:
$$
(42x^2y^3)\div(-14x^2y^4)=\frac{42x^2y^3}{-14x^2y^4}=\frac{3\cdot 14x^2y^3}{-14x^2y^4}=-\frac{3}{y}.
$$
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