Answer
$3y^3+2y^2+y$
Work Step by Step
We divide each term of the polynomial by the monomial as follows
$$
(18y^3 + 12y^2 + 6y) \div 6=\frac{18y^3 + 12y^2 + 6y}{6}
\\ =\frac{18y^3 }{6}+\frac{ 12y^2 }{6}+\frac{ 6y}{6}\\
=3y^3+2y^2+y
.
$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 32
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