Answer
$2$
Work Step by Step
We are given: $x=-1$, $y=2$, $z=-3$
We take into account the order of operations:
Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction
Thus, we have:
$$\frac{x^2+(z-y)^2}{4x^2+z^2}=\frac{(-1)^2+(-3-2)^2}{4(-1)^2+(-3)^2}\\
=\frac{1+(-5)^2}{4+9}=\frac{1+25}{13}=\frac{26}{13}=2
.$$
