Answer
$369$
Work Step by Step
We are given: $x=-1$, $y=2$, $z=-3$
We take into account the order of operations:
Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction
Thus, we have:
$$3x^2(y-3z)^2-6x=3(-1)^2(2-3(-3))^2-6(-1)\\
=3(2+9)^2+6=3(11)^2+6 =369
.$$
