Answer
$\frac{9}{4}$
Work Step by Step
We are given: $x=-3$, $y=4$, $z=6$
We take into account the order of operations:
Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction
Thus, we have:
$$\left(\frac{x+3y}{z}\right)^2=\left(\frac{-3+3*4}{6}\right)^2=\left(\frac{-3+12}{6}\right)^2\\
=\left(\frac{9}{6}\right)^2=\left(\frac{3}{2}\right)^2=\frac{3^2}{2^2}=\frac{9}{4}
.$$
