Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.1 - Fundamental Operations - Exercise - Page 214: 26

Answer

$2\frac{2}{3}$

Work Step by Step

Since $x=-1$ and $y=5$, we have $$ \frac{(y - x)^2 - 4y}{4x^2+2}=\frac{(5- (-1))^2 - 4(5)}{4(-1)^2+2}\\ =\frac{(5+1)^2 -20}{4 +2}=\frac{36-20}{6}\\ =\frac{16}{6}=\frac{8}{3}=2\frac{2}{3} .$$
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