Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 9

Answer

0.01 g, 0.005 g, 0.00225, 0.23%

Work Step by Step

For the measurement 2.22 g, we have The precision is 0.01 g The greatest possible error is one-half the precision $0.5\cdot 0.01\ g=0.005 \ g$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.005\ g}{2.22\ g}=0.00225$ The percent of error is $0.23\%$
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