Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 6

0.001 cm, 0.0005 cm, 0.00265, 0.27%

For the measurement 0.188 cm, we have The precision is 0.001 cm The greatest possible error is one-half the precision $0.5\cdot 0.001\ cm=0.0005 \ cm$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.0005\ cm}{0.188\ cm}=0.00265$ The percent of error is $0.27\%$.