Answer
$10,000\Omega$; $5, 000\ \Omega$; $0.0208$; $2.08\%$.
Work Step by Step
For the measurement 240,000 $\Omega$, we have:
The precision is 10,000 $\Omega$ (because the last non-zero digit $4$ is in the 10,000 place).
The greatest possible error is one-half the precision:
$0.5\cdot 10,000 \ \Omega =5, 000\ \Omega$.
The relative error is:
$relative~error=\dfrac{greatest~possible~error}{measurement}$
$\frac{5,000 \ \Omega}{240,000\ \Omega}=0.0208$.
The percent of error is $2.08\%$.