Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 2

Answer

$10,000\Omega$; $5, 000\ \Omega$; $0.0208$; $2.08\%$.

Work Step by Step

For the measurement 240,000 $\Omega$, we have: The precision is 10,000 $\Omega$ (because the last non-zero digit $4$ is in the 10,000 place). The greatest possible error is one-half the precision: $0.5\cdot 10,000 \ \Omega =5, 000\ \Omega$. The relative error is: $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{5,000 \ \Omega}{240,000\ \Omega}=0.0208$. The percent of error is $2.08\%$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.