Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 5

Answer

0.001 g, 0.0005 g, 0.0588, 0.59 %

Work Step by Step

For the measurement 0.085 g, we have The precision is 0.001 g The greatest possible error is one-half the precision $0.5\cdot 0.001\ g=0.0005 \ g$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.0005\ g}{0.085\ g}=0.00588$ The percent of error is $0.58\%$.
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