Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 11

Answer

0.01 kg; 0.005 kg; 0.005; 0.5 %

Work Step by Step

For the given measurement, we have The precision is 0.01 kg The greatest possible error is one-half the precision $0.5\cdot 0.01 \ kg= 0.005 \ kg$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.005\ kg}{1.00\ kg}=0.005$ The percent of error is $0.5\%$
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