Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 191: 17

Answer

1 in.; 0.5 in.; 0.00329; 0.33%

Work Step by Step

For the given measurement, we have The precision is 1 in The greatest possible error is one-half the precision $0.5\cdot 1\ in=0. 5 \ in$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.5\ in}{12 \ ft 8\ in}=\frac{0.5\ in}{152\ in}=0.0033$, (we used the fact $1 ft =12 in$) The percent of error is $0.33\%$.
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