Answer
$\dfrac{-2}{x^2}$
Work Step by Step
Simplify. $\sqrt[5] {\dfrac{-32}{x^{10}}}$
Therefore, $\sqrt[5] {\dfrac{-32}{x^{10}}}=\sqrt[5] {(\dfrac{-2}{x^2})^5}$
Thus, the given radical term can be written as:$\dfrac{-2}{x^2}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Test - Page 578: 9
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