Answer
$\dfrac{\sqrt[3] {25x}}{x}$
Work Step by Step
Simplify. $\dfrac{5}{ \sqrt [3]{5x^2}}$
Now, $\dfrac{5}{ \sqrt [3]{5x^2}}=(\dfrac{5}{ \sqrt [3]{5x^2}}) \cdot (\dfrac{\sqrt[3]{25x}}{ \sqrt[3]{25x}})$
or, $=\dfrac{5 \sqrt[3] {25x}}{5x}$
Thus, the given radical term can be written as:
$\dfrac{\sqrt[3] {25x}}{x}$
