Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 13

Answer

$(2x+y^2)\sqrt[3]{x}$

Work Step by Step

Simplify. $\sqrt[3] {8x^4} +\sqrt[3] {xy^6}$ Therefore, $\sqrt[3] {8x^4} +\sqrt[3] {xy^6}=\sqrt[3] {8x^3 \cdot x} +\sqrt[3] {x \cdot y^6}$ or, $=2x \sqrt[3]{x} +y^2\sqrt[3]{x}$ Thus, the given radical term can be written as:$(2x+y^2)\sqrt[3]{x}$
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