Answer
a) 6, b) $x \leq 4$
Work Step by Step
Given: $f9x)=\sqrt{8-2x}$
a) Need to find $f(-14)$
$f(-14)=\sqrt{8-2(-14)}=\sqrt{36}=6$
b) Domain can be determined as follows:
$8-2x\geq 0$
or, $-2x\geq -8$
or, $2x \leq 8$
Thus, $x \leq 4$