Answer
$\dfrac{1}{81}$
Work Step by Step
Simplify. $27^{\frac{-4}{3}}$
$27^{\frac{-4}{3}}=(3^3)^{\frac{-4}{3}}$
or, $=(3)^{(3)(\frac{-4}{3})}$
Thus, $=3^{-4}$
It can be written as $\dfrac{1}{81}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Test - Page 578: 2
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