Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 12

Answer

$-7\sqrt 2$

Work Step by Step

Simplify. $3\sqrt {18} -4\sqrt {32}$ Therefore, $3\sqrt {18} -4\sqrt {32}=3 \sqrt { 2 \cdot 3 \cdot 3} - 4 \sqrt { 2 \cdot 4 \cdot 4}$ or, $=9\sqrt { 2} - 16 \sqrt { 2}$ Thus, the given radical term can be written as: $-7\sqrt 2$
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