Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 531: 78

Answer

$=2xyz^2\sqrt[4]{2x^{2}z}$.

Work Step by Step

The given expression is $\sqrt[4]{4x^2y^3z^3}\cdot \sqrt[4] {8x^4yz^6}$ Apply product rule $\sqrt[n] a \cdot \sqrt[n] b = \sqrt[n] {ab}$ $\sqrt[4]{4x^2y^3z^3\cdot 8x^4yz^6}$ $\sqrt[4]{2^2x^2y^3z^3\cdot 2^3x^4y^1z^6}$ Use $a^n\cdot a^m = a^{m+n}$ $\sqrt[4]{2^{2+3}x^{2+4}y^{3+1}z^{3+6}}$ $\sqrt[4]{2^{5}x^{6}y^{4}z^{9}}$ Further simplify by using product rule. $=\sqrt[4]{2^{4+1}x^{4+2}y^{4}z^{4+4+1}}$ $=\sqrt[4]{2^{4}2x^{4}x^{2}y^{4}z^{4}z^{4}z^1}$ $=\sqrt[4]{(2xyzz)^42x^{2}z}$ $=2xyzz\sqrt[4]{2x^{2}z}$. $=2xyz^2\sqrt[4]{2x^{2}z}$.
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