Answer
$2x^2\sqrt[4]{5x^2}$
Work Step by Step
Write $80$ as $16(5)$ to obtain:
$=\sqrt[4]{16(5)x^{10}}
\\=\sqrt[4]{2^4(5)x^{10}}$
RECALL:
$\sqrt[n]{a^n}=a$
Factor the radicand (expression inside the radical sign) so that at least one factor is a perfect fourth power, and then use the rule above to simplify and obtain:
$=\sqrt[4]{(2^4x^8) \cdot 5x^2}
\\=\sqrt[4]{2^4(x^2)^4 \cdot 5x^2}
\\=2x^2\sqrt[4]{5x^2}$
