Answer
$-2y\sqrt[3]{2x^2}$
Work Step by Step
Factor the radicand (expression inside the radical sign) so that one factor is a perfect cube, and then simplify to obtain:
$=\sqrt[3]{(-8y^3)(2x^2)}
\\=\sqrt[3]{(-2y)^3(2x^2)}
\\=-2y\sqrt[3]{2x^2}$