Answer
$\dfrac{1}{3}$
Work Step by Step
RECALL:
(i) $a^{-\frac{m}{n}}=\dfrac{1}{a^{\frac{m}{n}}}$
(ii) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$
Use the rules above to obtain:
$=\dfrac{1}{27^{\frac{1}{3}}}
\\=\dfrac{1}{\sqrt[3]{27}}
\\=\dfrac{1}{\sqrt[3]{3^3}}
\\=\dfrac{1}{3}$
