Answer
$\dfrac{1}{y^{\frac{1}{6}}}$
Work Step by Step
Use the rule $(a^m)^n= a^{mn}$ to obtain:
$=y^{-\frac{2}{3} \cdot \frac{1}{4}}
\\=y^{-\frac{2(1)}{3(4)}}
\\=y^{-\frac{2}{12}}
\\=y^{-\frac{1}{6}}$
Use the rule $a^{-m} = \dfrac{1}{a^m}$ to obtain:
$=\dfrac{1}{y^{\frac{1}{6}}}$
