Answer
$x^{16}y^{8}$
Work Step by Step
Simplify. $(\sqrt [5]{{x^4y^2}})^{20}$
Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$
Thus,
$(\sqrt [5]{{x^4y^2}})^{20}=(x^4y^2)^{\frac{20}{5}}=(x^4y^2)^{4}$
or, $=(x^4)^{4}(y^2)^4$
or, $=x^{16}y^{8}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 110
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