Answer
$\dfrac{1}{3}$
Work Step by Step
RECALL:
(i) $a^{-\frac{m}{n}}=\dfrac{1}{a^{\frac{m}{n}}}$
(i) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$
Use the rules above to obtain:
$=\dfrac{1}{9^{\frac{1}{2}}}
\\=\dfrac{1}{\sqrt{9}}
\\=\dfrac{1}{3}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 40
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