Answer
$\sqrt[3]{4a^2}$
Work Step by Step
RECALL:
(i) $\sqrt[n]{a} = a^{\frac{1}{n}}$
(ii) $\sqrt[n]{a^m} = a^{\frac{m}{n}}$
(iii) $(ab)^m = a^mb^m$
(iv) $(a^m)^n=a^{mn}$
Use the rules above to obtain:
$=\left((2a)^{\frac{1}{6}}\right)^4
\\=(2a)^{\frac{1}{6} \cdot 4}
\\=(2a)^{\frac{2}{3}}
\\=\sqrt[3]{(2a)^2}
\\=\sqrt[3]{4a^2}$
