Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 122

Answer

$\dfrac{2x^3}{y}$

Work Step by Step

Simplify. $(8x^{-6}y^3)^{1/3}(x^{5/6}y^{-1/3})^6$ or, $=(2^3)^{1/3}(x^{-6})^{1/3}(y^3)^{1/3}(x^{5/6})^6(y^{-1/3})^6$ or,$=2(x^{-2})(y)(x^{5})(y^{-2})$ or, $=2x^{-2+5}y^{1+(-2)}$ or, $=2x^3y^{-1}$ or, $=\dfrac{2x^3}{y}$
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