Answer
$3x-8+\displaystyle \frac{20}{x+5}$
Work Step by Step
Dividing with (x-c) ... $c=-5$
$\begin{array}{rrrr}
\underline{-5}| &3 & 7 &-20\\
& & -15 & 40 \\
&--&--&--\\
&3 & -8 &20 \end{array}$
Quotient = $ 3x-8$
Remainder = $20$
$\displaystyle \frac{dividend}{divisor}=quotient+\frac{remainder}{divisor}$
$\displaystyle \frac{3x^{2}+7x-20}{x+5}$ = $3x-8+\displaystyle \frac{20}{x+5}$
