Answer
$2ab-a-3b$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{18a^{3}b^{2}-9a^{2}b-27ab^{2}}{9ab}=\frac{18a^{3}b^{2}}{9ab}-\frac{9a^{2}b}{9ab}-\frac{27ab^{2}}{9ab}$
= $2ab-a-3b$
