Answer
$7x-\displaystyle \frac{7}{4}-\frac{4}{x}$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{28x^{3}-7x^{2}-16x}{4x^{2}}=\frac{28x^{3}}{4x^{2}}-\frac{7x^{2}}{4x^{2}}-\frac{16x}{4x^{2}}$
= $7x-\displaystyle \frac{7}{4}-\frac{4}{x}$
