Answer
$10x-\displaystyle \frac{10}{7}-\frac{2}{x}$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{70x^{3}-10x^{2}-14x}{7x^{2}}=\frac{70x^{3}}{7x^{2}}-\frac{10x^{2}}{7x^{2}}-\frac{14x}{7x^{2}}$
= $10x-\displaystyle \frac{10}{7}-\frac{2}{x}$
