Answer
$6x-\displaystyle \frac{3}{y}-\frac{2}{xy^{2}}$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{36x^{4}y-18x^{3}y^{2}-12x^{2}y}{6x^{3}y^{3}}=\frac{36x^{4}y^{3}}{6x^{3}y^{3}}-\frac{18x^{3}y^{2}}{6x^{3}y^{3}}-\frac{12x^{2}y}{6x^{3}y^{3}}$
= $6x-\displaystyle \frac{3}{y}-\frac{2}{xy^{2}}$
