Answer
The graph is shown in the image file.
Work Step by Step
The given equation of the line is
$\Rightarrow 4x=8-2y$
Plug $y=0$ for the $x−$intercept.
$\Rightarrow 4x=8-2(0)$
Simplify.
$\Rightarrow 4x=8$
Divide both sides by $4$.
$\Rightarrow \frac{4x}{4}=\frac{8}{4}$
Simplify.
$\Rightarrow x=2$
The $x−$intercept is 2, so the line passes through (2,0).
Plug x=0 for the y−intercept.
$\Rightarrow 4(0)=8-2y$
Simplify.
$\Rightarrow 0=8-2y$
Add $2y$ to both sides.
$\Rightarrow 0+2y=8-2y+2y$
Simplify.
$\Rightarrow 2y=8$
Divide both sides by $2$.
$\Rightarrow \frac{2y}{2}=\frac{8}{2}$
Simplify.
$\Rightarrow y=4$
The $y−$intercept is $4$, so the line passes through $(0,4)$.
Checkpoint plug $y=2$.
$\Rightarrow 4x=8-2(2)$
Simplify.
$\Rightarrow 4x=8-4$
$\Rightarrow 4x=4$
Divide both sides by $4$.
$\Rightarrow \frac{4x}{4}=\frac{4}{4}$
Simplify.
$\Rightarrow x=1$
The checkpoint is $(1,2)$.
Plot the three points determined above. Draw a straight line through the points $(2,0)$ and $(0,4)$. We notice that the checkpoint $(1,2)$ also belongs to the line, therefore our graph is correct.
