Answer
The graph is shown in the image file.
Work Step by Step
The given equation of the line is
$\Rightarrow x+2y=4$
Plug $y=0$ for the $x−$intercept.
$\Rightarrow x+2(0)=4$
Simplify.
$\Rightarrow x=4$
The $x−$intercept is $4$, so the line passes through $(4,0)$.
Plug $x=0$ for the $y−$intercept.
$\Rightarrow (0)+2y=4$
Simplify.
$\Rightarrow 2y=4$
Divide both sides by $2$.
$\Rightarrow \frac{2y}{2}=\frac{4}{2}$
Simplify.
$\Rightarrow y=2$
The $y−$intercept is $2$, so the line passes through $(0,2)$.
Checkpoint plug $x=2$.
$\Rightarrow (2)+2y=4$
Simplify.
$\Rightarrow 2+2y=4$
Subtract $2$ from both sides.
$\Rightarrow 2+2y-2=4-2$
Simplify.
$\Rightarrow 2y=2$
Divide both sides by $2$.
$\Rightarrow \frac{2y}{2}=\frac{2}{2}$
$\Rightarrow y=1$
The checkpoint is (2,1).
Plot the three points determines above. Draw a straight line through the points $(4,0)$ and $(0,2)$. We notice that the checkpoint $(2,1)$ also belongs to the line, therefore our graph is correct.
