Answer
See below.
Work Step by Step
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x^2-2x}{x-5}$
$(\frac{f}{g})(4)=\frac{4^2-2\cdot4}{4-5}=\frac{16-8}{-1}=-8$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Review Exercises - Page 173: 32
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