Answer
$(-\infty,5)\cup(5,+\infty)$
Work Step by Step
$(\frac{f}{g})(x)=\frac{x^2-2x}{x-5}$ since the denominator can't be equal to 0 $x\ne5$
the domain is $(-\infty,5)\cup(5,+\infty)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Review Exercises - Page 173: 34
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